9x^2-23x-12=0

Solution for 9x^2-23x-12=0 equation:

9x^2-23x-12=0

a = 9; b = -23; c = -12;
Δ = b2-4ac
Δ = -232-4·9·(-12)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-31}{2*9}=\frac{-8}{18}
=-4/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+31}{2*9}=\frac{54}{18}
=3
$